9. Cottonmouth Litter Size. Refer to Problem 8. Find a 98 % confidence interval for the difference between the mean litter sizes of cottonmouths in Florida and Virginia. Interpret your result.

Short Answer

Expert verified

on average, the number of young per litter of cottonmouths in Florida is less than that in Virginia.

Step by step solution

01

Step 1:Given information

The summary statistics on the data of the number of young per litter for 24 female cottonmouths in Florida and 44 female cottonmouths in Virginia is obtained as follows:


FloridaVirginia
size2444
mean5.467.59
standard deviation1.592.68
02

Step 2:Explaination

Here we assumed that the litter sizes of cottonmouths in both states are approximately normally distributed. Also the samples are independent and the population standard deviations are not known and are not assumed to be equal. Therefore we use nonpooled t-procedures in this illustration for comparing the differences of the population means.

Here we set up the null and alternative hypotheses as follows:

H0:μ1=μ2(There is no evidence to claim that, on average, the number of young per litter of cottonmouths in Florida is less than that in Virginia.)

Versus

HA:μ1<μ2(There is no evidence to claim that, on average, the number of young per litter of cottonmouths in Florida is less than that in Virginia.)

This is a left-tailed test.

Also we set up α=0.01level of significance.

03

Step 3:Observation

Using MINITAB, we conduct the nonpooled t-test under the above stated null hypothesis as follows:

1 Choose Stat ? Basic Statistics ? 2-Sample t...

2 Select the Samples in different columnsoption button

3 Click in the First text box and specify Florida

4 Click in the Secondtext box and specify Virginia

5 Uncheck theAssume equal variances check box

6 Click the Options ... button

7 Click in the Confidence leveltext box and type 99

8 Click in theTest differencetext box and type 0

9 Click the arrow button at the right of theAlternative drop-down list box and select less than

10 ClickOK twice

The output for the above test is obtained as follows:

04

Step 4:Result

We observe that zero is not contained in the 98 % confidence interval of the difference between the two population means. Therefore we conclude that the two population means are different. Also we observe that the confidence interval is less than zero. Hence there is enough evidence to conclude that, on average, the number of young per litter of cottonmouths in Florida is less than that in Virginia.

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Most popular questions from this chapter

You know that the population standard deviations are equal.

In the paper "The Relation of Sex and Sense of Direction to Spatial Orientation in an Unfamiliar Environment" (Journal of Environmental Psychology, Vol. 20, pp. 17-28), J. Sholl et al. published the results of examining the sense of direction of 30 male and 30 female students. After being taken to an unfamiliar wooded park, the students were given some spatial orientation tests, including pointing to the south, which tested their absolute frame of reference. The students pointed by moving a pointer attached to a 360°protractor. Following are the absolute pointing errors, in degrees, of the participants.

At the 1% significance level, do the data provide sufficient evidence to conclude that, on average, males have a better sense of direction and, in particular, a better frame of reference than females? (Note: x¯1=37.6,s1=38.5,x¯2=55.8,ands2=48.3.)

Suppose that you want to perform a hypothesis test to compare the means of two populations, using independent simple random samples. Assume that the two distributions of the variable under consideration have the same shape, but are not normal, and both sample sizes are large. Answer the following questions and explain your answers.

a. Is it permissible to use the pooled t-test to perform the hypothesis test?

b. Is it permissible to use the Mann-Whitney test to perform the hypothesis test?

c. Which procedure is preferable, the pooled t-test or the Mann-Whitney test?

Identify the assumption for using the two means ztest and the two mean zinterval procedure that renders those procedures generally impractical.

Consider the quantitiesμ1,σ1,x¯1,s1,μ2,σ2,x^2, and s2.

a. Which quantities represent parameters and which represent statistics?

b. Which quantities are fixed numbers and which are variables?

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