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Chapter 10: Q.10.122 (page 442)

In exercise 10.117-10.122, the null hypothesis is H0:μ1=μ2and the alternative hypothesis is as specified. we have provided data from a simple random paired sample from the two population under consideration. in each case, use the paired ttest to perform the required hypothesis test at the 10%significance level.

Hα:μ1>μ2

Short Answer

Expert verified

The null hypothesis is rejected.

Step by step solution

01

Given Information

Given in the question that,

H0:μ1=μ2Hα:μ1>μ2

Level of significance is 0.1we have to determine the paired tt-test for the given values.

02

Explanation

Let's compute the sample mean as follow:

d¯=∑dn=1810=1.8

Calculate the standard deviation :

sd=∑di2-∑di2nn-1=138-(18)21010-1=3.4254

The formula of test statistics is

t=d¯sdn

Substitute the given values

t=1.83.425410=1.66

The value of degree of freedom is:

dof=n-1=10-9=1

The critical value for the level of significance 0.1is1.383

The value of test statistic is fall in the rejection region.

Therefore, the null hypothesis is rejected.

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Most popular questions from this chapter

In this Exercise, we have provided summary statistics for independent simple random samples from two populations. In each case, use the pooled t-lest and the pooledt-interval procedure to conduct the required hypothesis test and obtain the specified confidence interval.
x¯1=20,s1=4,n1=30,x¯2=18,s2=5,n2=40

a. Right-tailed test, α=0.05

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