Chapter 10: Q.10.130 (page 443)

Sleep. Refer to Exercise 10.124.
a. Determine a $90 %$ confidence interval for the additional sleep that would be obtained, on average, by using laevohysocyamine hydrobromide.
b. Repeat part (a) for a $98 %$ confidence level.

Short Answer

Expert verified

a). $(1.1695, 3.4905)$ is the $90 %$ confidence interval for the data.

b). $(0.5483, 4.1162)$ is the data's $98 %$ confidence interval.

Step by step solution

Part (a) Step 1: Given Information

The data is displayed below with the values $\bar{d} = 2.33, s_{d} = 2.002$ .

$1.9$	$0.8$	$1.1$	$0.1$	$- 0.1$
$4.4$	$5.5$	$1.6$	$4.6$	$3.4$

Part (a) Step 2: Explanation

The degree of freedom is,

$dof = n - 1$

$= 10 - 1$

$= 9$

The critical value for the level of significance is localid="1651282848943" $\pm 1.833$ .

The confidence level is,

$C I = \bar{d} \pm t_{\frac{a}{2}} \frac{s_{d}}{\sqrt{n}}$

$= 2.33 \pm (1.833) \frac{2.002}{\sqrt{10}}$

$= (1.1695, 3.4905)$

Part (b) Step 1: Given Information

The data is displayed below with the values $\bar{d} = 2.33, s_{d} = 2.002$ .

$\begin{array}{lllllc} 1.9 & 0.8 & 1.1 & 0.1 & - 0.1 \\ 4.4 & 5.5 & 1.6 & 4.6 & 3.4 \end{array}$

Part (b) Step 2: Explanation

The degree of freedom is,

$dof = n - 1$

$= 10 - 1$

$= 9$

The critical value for level of significance is $\pm 2.821$ .

The confidence level is,

$C I = \bar{d} \pm t_{\frac{a}{2}} \frac{s_{d}}{\sqrt{n}}$

$= 2.33 \pm (2.821) \frac{2.002}{\sqrt{10}}$

$= (0.5483, 4.1162)$

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Sleep. Refer to Exercise 10.124.
a. Determine a $90 %$ confidence interval for the additional sleep that would be obtained, on average, by using laevohysocyamine hydrobromide.
b. Repeat part (a) for a $98 %$ confidence level.

Short Answer

Step by step solution

Part (a) Step 1: Given Information

Part (a) Step 2: Explanation

Part (b) Step 1: Given Information

Part (b) Step 2: Explanation

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Sleep. Refer to Exercise 10.124.a. Determine a 90% confidence interval for the additional sleep that would be obtained, on average, by using laevohysocyamine hydrobromide.b. Repeat part (a) for a 98% confidence level.

Short Answer

Step by step solution

Part (a) Step 1: Given Information

Part (a) Step 2: Explanation

Part (b) Step 1: Given Information

Part (b) Step 2: Explanation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Discrete Mathematics

Calculus

Logic and Functions

Probability and Statistics

Mechanics Maths

Theoretical and Mathematical Physics

Study anywhere. Anytime. Across all devices.

Sleep. Refer to Exercise 10.124.
a. Determine a $90 %$ confidence interval for the additional sleep that would be obtained, on average, by using laevohysocyamine hydrobromide.
b. Repeat part (a) for a $98 %$ confidence level.