Measuring Treadwear. Refer to Exercise 10.126 and find a 95% confidence interval for the mean difference in measurement by the weight and groove methods.

Short Answer

Expert verified

(1.59,5.92) is the data's 95% confidence interval.

Step by step solution

01

Given Information

The given data is,

MethodMethod30.528.730.925.931.923.330.423.127.323.720.420.924.516.120.919.918.915.213.711.511.411.2

02

Explanation

Below is the given data,

MethodMethodDifference=dd230.528.71.83.2430.925.952531.923.38.673.9630.423.17.353.2927.323.73.612.9620.420.9-0.50.2524.516.18.470.5620.919.91118.915.23.713.6913.711.52.24.8411.411.20.20.0441.3258.83

03

Explanation

The sample mean is,

d¯=dn

=41.311

localid="1651285684383" =3.7545

The standard deviation is,

sd=di2-di2nn-1

=258.83-(44.3)21111-1

=3.2213

04

Explanation

The degree of freedom is,

dof=n-1

=11-1

=10

The level of significance's critical value is ±2.228.

The confidence level is,

CI=d¯±ta2sdn

=3.7545±(2.228)3.221311

=(1.59,5.92)

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