A variable of two population has a mean of 7.9and standard deviation of 5.4for one of the population and a mean of 7.1and a standard deviation of 4.6 for the other population.

a. For independent samples of sizes 3and6respectively find the mean and standard deviation of x1-x2

b. Must the variable under consideration be normally distributed on each of the two population for you to answer part (a) ? Explain your answer.

b. Can you conclude that the variable x1-x2is normally distributed? Explain your answer.

Short Answer

Expert verified

(a) μ1-μ2=0.8and σx1-x2=3.64

(b) No, we cannot conclude that the variable under consideration be normally distributed .

(c) No ,we cannot conclude that the variable is normally distributed.

Step by step solution

01

Part (a)  Step 1: Given Information 

Given in the question that,

Population 1: Mean is 7.9, standard deviation is 5.4, and sample size is 3

Population 2: Mean is 7.1and standard deviation is 4.6and sample size is 6we have to calculate the mean and standard deviation of x1-x2

02

Part (a) Step 2: Explanation 

Mean:

x1-x2=μ1-μ2=7.9-7.1=0.8

Standard deviation:

σx¯1-x¯2=σ12n1+σ22n2

σx¯1-x¯2=5.423+4.626

σx¯1-x¯2=3.64

hence, mean=0.8standard deviation=3.64

03

Part (b)  Step 1: Given Information 

Given in the question that,

Population 1: Mean is 7.9, standard deviation is 5.4, and sample size is 3Population 2: Mean is 7.1and standard deviation is 4.6and sample size is

6.we have To calculate If the variable under consideration must be normally distributed on each of the population given.

04

Part (b) Step 2: Explanation 

from part ( a) mean and standard deviation are 0.8and3.64

Regardless of the distribution of variables on an individual population, the distribution of mean and standard deviation ofx1-x2remains the same.

The standard deviation formula for x1-x2also based on the assumption that the samples are independent.

As a result, the variable under examination does not have to be regularly distributed throughout the entire population.

05

Part (c)  Step 1: Given Information 

Given in the question that,

Population 1: Mean is 7.9, standard deviation is 5.4, and sample size is 3Population 2: Mean is 7.1and standard deviation is 4.6and sample size is6

06

Part (c) Step 2: Explanation 

It is unclear whether the two populations are typically distributed based on the information provided. The sample sizes of3and6 are also somewhat tiny. As a result, the variablex1-x2 cannot be considered to be regularly distributed.

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Most popular questions from this chapter

Two-Tailed Hypothesis Tests and CIs. As we mentioned on page 413, the following relationship holds between hypothesis tests and confidence intervals: For a two-tailed hypothesis test at the significance level α, the null hypothesis H0:μ1=μ2 will be rejected in favor of the alternative hypothesis H2:μ1μ2 if and only if the (1-α)-level confidence interval for μ1-μ2 does not contain 0. In each case, illustrate the preceding relationship by comparing the results of the hypothesis test and confidence interval in the specified exercises.

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