TV Location. The Television Bureau of Advertising publishes a report titled TV Basics for the purpose of providing information to help advertisers make the most effective and efficient use of local and national spot television advertisements. The following table gives a percentage distribution for the location of a television set in the home.

Suppose that a home television set is randomly selected. What is the probability that it is

(a) located in a bedroom?

(b) not located in a bedroom?

(c) located in the kitchen, dining room, basement, or garage?

The given statement is:

The Television Bureau of Advertising publishes a report titled TV Basics for the purpose of providing information to help advertisers make the most effective and efficient use of local and national spot television advertisements.

The following table gives a percentage distribution for the location of a television set in the home.

Total percentage of TV Located in the bedroom:

24% in the master bedroom$+$19% in the child or other bedroom$=43\%$

role="math" localid="1651770355044" $$\begin{gathered} P(\mathrm{Television}\mathrm{in}\mathrm{bedroom})=43\% \\ =\frac{43}{100} \\ =0.43 \end{gathered}$$

$$\begin{gathered} P(\mathrm{Television}\mathrm{not}\mathrm{located}\mathrm{in}\mathrm{bedroom})=1-P(\mathrm{Television}\mathrm{located}\mathrm{in}\mathrm{bedroom}) \\ =1-0.43 \\ =0.57 \end{gathered}$$

The total percentage of TV Located in the kitchen, dining room, basement, or garage is:

5% in the kitchen or dining room$+$5% in the basement and garage$=10\%$

Therefore, the probability is:

$$\begin{gathered} =10\% \\ =0.1 \end{gathered}$$