Which of the following numbers could not possibly be a probability? Justify your answer.

$$\begin{gathered} \left(a\right)0.462 \\ \left(b\right)-0.201 \\ \left(c\right)1 \end{gathered}$$

The given statement is:

Which of the following numbers could not possibly be a probability?

$\left(a\right)0.462,\left(b\right)-0.20,\left(c\right)1$

The given chance of an incident is 0.462.

We know that an event's probability ranges from 0 to 1, and both are included.

0.462 is a number that falls between 0 and 1.

As a result, the chance of an event is 0.462.

We know that there can't be a negative probability, and also it can't be more than one.

It is assumed that an event's probability is$-0.201$.

It is negative and does not fall between 0 and 1.

As a result, $-0.201$does not represent the chance of an event occurring.

The probability of an event is not equal to $-0.201$.

Given possible probability is 1.

Because the chance of an event ranges from 0 to 1 and both are included,

As a result, the chance of an event is possible for probability 1.

Therefore, 1 is the probability of an event occurring.