In the article "Assessing Friendship Motivation During Preadolescence and Early Adolescence", J. Richard and B. Schneider described the properties of the Friendship Motivation Scale for Children (FMSC), a scale designed to assess children's desire for friendships. Two interesting conclusions are that friends generally report similar levels of the FMSC and girls tend to score higher on the FMSC than boys. Boys in the seventh grade scored a mean 9.32with a standard deviation of data-custom-editor="chemistry" 1.71,and girls in the seventh grade scored a mean of 10.04with a standard deviation of 1.83.Assuming that FMSC scores are normally distributed, determine the percentage of seventh-grade boys who have FMSC scores within

Part (a): One standard deviation to either side of the mean.

Part (b): Two standard deviation to either side of the mean.

Part (c): Three standard deviation to either side of the mean.

Part (d): Repeat parts (a)-(c) for seventh-grade girls.

Short Answer

Expert verified

Part (a): The percentage of seventh-grade boys who have FMSC scores within one standard deviation to either side of the mean is 7.61and 11.03.

Part (b): The percentage of seventh-grade boys who have FMSC scores within two standard deviation to either side of the mean is 5.9and 12.74.

Part (c): The percentage of seventh-grade boys who have FMSC scores within three standard deviation to either side of the mean is 4.19and 14.45.

Part (d): The percentage of seventh-grade girls who have FMSC scores within one standard deviation to either side of the mean is 8.21and 11.87.

The percentage of seventh-grade girls who have FMSC scores within two standard deviation to either side of the mean is 6.38and 13.7.

The percentage of seventh-grade girls who have FMSC scores within three standard deviation to either side of the mean is4.55and15.53.

Step by step solution

01

Part (a) Step 1. Given information.

The given mean of boys is 9.32and standard deviation is 1.71.

The given mean of girls is 10.04 and standard deviation is1.83.

02

Part (a) Step 2. Find the one standard deviation above and below mean of boys.

Property 1of the 68.26-95.44-99.74rule says 68.26%of all FMSC scores of boys have duration within one standard deviation to either side of the mean.

One standard deviation below mean is given below,

μ-σ=9.32-1.71=7.61

One standard deviation above mean is given below,

μ+σ=9.32+1.71=11.03

Therefore, 68.26%of all FMSC scores of boys are between7.61,11.03.

03

Part (b) Step 1. Find the two standard deviation above and below mean of boys.

Property 2of the 68.26-95.44-99.74rule says 95.4%of all FMSC scores of boys have duration within two standard deviation to either side of the mean.

Two standard deviation below mean is given below,

μ-σ2=9.32-21.71=5.9

Two standard deviation above mean is given below,

μ+σ2=9.32+21.71=12.74

Therefore,95.4%of all FMSC scores of boys are between5.9,12.74.

04

Part (c) Step 1. Find the three standard deviation above and below mean of boys.

Property 3of the 68.26-95.44-99.74rule says 99.74%of all FMSC scores of boys have duration within three standard deviations to either side of the mean.

Three standard deviation below mean is given below,

μ-3σ=9.32-31.71=4.19

Three standard deviation above mean is given below,

μ+3σ=9.32+31.71=14.45

Therefore, 99.74%of all FMSC scores of boys are between4.19,14.45.

05

Part (d) Step 1. Find the one standard deviation above and below mean of girls.

Property 1of the 68.26-95.44-99.74rule says 68.26%of all FMSC scores of girls have duration within one standard deviation to either side of the mean.

One standard deviation below mean is given below,

μ-σ=10.04-1.83=8.21

One standard deviation above mean is given below,

μ+σ=10.04+1.83=11.87

68.26%of all FMSC scores of girls are between 8.21,11.87.

06

Part (d) Step 2. Find the two standard deviation above and below mean of girls.

Property 2of the 68.26-95.44-99.74rule says 95.4%of all FMSC scores of girls have duration within two standard deviation to either side of the mean.

Two standard deviation below mean is given below,

μ-2σ=10.04-21.83=6.38

Two standard deviation above mean is given below,

μ+2σ=10.04+21.83=13.7

Therefore, 95.4%of all FMSC scores of girls are between 6.38,13.7.

07

Part (d) Step 3. Find the three standard deviation above and below mean of girls.

Property 3of the 68.26-95.44-99.74rule says 99.74%of all FMSC scores of girls have duration within three standard deviations to either side of the mean.

Three standard deviation below mean is given below,

localid="1652508622327" μ-3σ=10.04-31.83=4.55

Three standard deviation above mean is given below,

localid="1652508624972" μ+3σ=10.04+31.83=15.53

Therefore, 99.74%of all FMSC scores of girls are between 4.55,15.53.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free