Use table IIto obtain each shaded area under the standard normal curve

Short Answer

Expert verified

Part a: The required area is, 0.9500.

Part b: The required area is, 0.9802.

Part c: The required area is, 0.2006.

Partd: The required area is,0.1010.

Step by step solution

01

Part a Step 1. Given information

02

Part a Step 2. Let us find the area for the given diagram.

The area under the standard normal curve that lies between -1.96and 1.96equals the area to the left of 1.96minus the area to the left of -1.96.Standard normal table shows that these latter two areas are0.9750and0.0250, respectively. So, the required area is,0.9750-0.0250=0.9500.

03

Part b Step 1. Given information

04

Part b Step  2. Let us find the area for the given diagram.

The area under the standard normal curve that lies between -2.33and 2.33equals the area to the left of 2.33minus the area to the left of -2.33. Standard normal table shows that these latter two areas are 0.9901and 0.0099,respectively. So, the required area is,role="math" localid="1652687589152" 0.9901-0.0099=0.9802.

05

Part c Step 1. Given information

06

Part c Step 2. Let us find the area for the given diagram.

First find the area to the left of -1.28and 1.28. Standard normal table shows that these latter two areas are 0.1003and 0.8997, respectively. The area under the standard normal curve that lies to the right of 1.28is, 1-0.8997=0.1003. Therefore, the area under the standard normal curve that lies to the left of -1.28or to the right of1.28is,0.1003+0.1003=0.2006.

07

Part d Step 1. Given information

08

Part d Step 2. Let us find the area for the given diagram.

First find the area to the left of -1.64and 1.64. Standard normal table shows that these latter two areas are 0.9495and 0.0505, respectively. The area under the standard normal curve that lies to the right of 1.64is, 1-0.9495=0.0505. The area under the standard normal curve that lies to the left of-1.64or to the right of1.64is,0.0505+0.0505=0.1010.

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