7.47 Baby Weight. The paper "Are Babies Normal?" by T. Clemons and M. Pagano (The American Statistician, Vol. 53, No, 4. pp. 298-302) focused on birth weights of babies. According to the article, the mean birth weight is3369 grams (7 pounds, 6.5 ounces) with a standard deviation of 581 grams.
a. Identify the population and variable.
b. For samples of size 200, find the mean and standard deviation of all possible sample mean weights.
c. Repeat part (b) for samples of size400.

Short Answer

Expert verified

(a) The population is made up of all newborn newborns, and the population variable is their weight.

(b) The mean is 3369gmand the standard deviation is41.08gm.

(c) The Mean is 3369gmand the standard deviation is 29.05gm.

Step by step solution

01

Part (a) Step 1: Given information

The mean birth weight is 3369 grams (7pounds, 6.5ounces) with a standard deviation of 581grams.

02

Part (a) Step 2: Explanation

All of the newly born babies make up the population.
The weight of a newborn baby is the population variable.
As a result, the population is made up of all newborn newborns, and the population variable is their weight.

03

Part (b) Step 1: Given information

To find the mean and standard deviation of all possible sample mean weights for samples of size 200. Where the mean birth weight is 3369grams, and the standard deviation of 581grams.

04

Part (b) Step 2: Explanation

The sample size is limited in comparison to the population size.

Standard deviation of all possible sample means is σX=σn
Where, the standard deviation for the population:localid="1651037316481" σ=581gm
Then the sample size isn=200
So,

σX=σn

=581200

localid="1651037567796" =41.08gm

Hence, mean of all possible sample means localid="1651037663812" μ=3369gm

As a result, mean is 3369gmand standard deviation is localid="1651037574449" 41.08gm.

05

Part (c) Step 1: Given information

To determine part (b) for samples of size 400. Where the mean birth weight is 3369grams, and the standard deviation of 581 grams.

06

Part (c) Step 2: Explanation

Standard deviation of all possible sample mean is σX=σn

Where the sample size n=400, Mean of all possible means μ=3369gm

So,

σX=σn

=581400

=29.05gm
As a result, Mean is 3369gmand standard deviation is29.05gm.

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Refer to Exercise 7.7 on page 295.

a. Use your answers from Exercise 7.7(b) to determine the mean, μs, of the variable x¯for each of the possible sample sizes.

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