Population data: 2,5,8

Part (a): Find the mean, μof the variable.

Part (b): For each of the possible sample sizes, construct a table similar to Table 7.2on the page 293and draw a dotplot for the sampling for the sampling distribution of the sample mean similar to Fig 7.1on page 293.

Part (c): Construct a graph similar to Fig 7.3and interpret your results.

Part (d): For each of the possible sample sizes, find the probability that the sample mean will equal the population mean.

Part (e): For each of the possible sample sizes, find the probability that the sampling error made in estimating the population mean by the sample mean will be0.5or less, that is, that the absolute value of the difference between the sample mean and the population mean is at most 0.5.

Short Answer

Expert verified

Part (a): The mean μis .

Part (b): When localid="1652546343925" n=1,

When localid="1652546346019" n=2,

When localid="1652546348144" n=3,

Part (c): The dot plot is given below,

Part (d): The probability that the sample mean will equal the population mean are 13,13,0.

Part (e): The probability that the sampling error made in estimating the population are13,13,0.

Step by step solution

01

Part (a) Step 1. Given information

Consider the given question,

The population data is2,5,8.

02

Part (a) Step 2. Find the mean of the variable.

The mean μis given below,

μ=xiN=2+5+83=153=5

03

Part (b) Step 1. Construct a table. 

For each of the possible sample sizes, we construct a table.

If the sample size taken n=1,

If the sample size taken n=2,

If the sample size taken n=3,

04

Part (c) Step 1. Construct the dot plot.

We will construct the dot plot for the sampling distribution of the sample mean.

To construct dot plot for the sampling distribution of the sample mean,


05

Part (d) Step 1. Find the probability that the sample mean will equal the population mean.

We can observe that from the dot plot there is one dot corresponding to μ=5.

Hence, the probability that sample mean will be equal to population mean for n=1is role="math" localid="1652545895359" 13.

Similarly, the probability that sample mean will be equal to population mean for data-custom-editor="chemistry" n=2is 13.

From the dot plot, we can see that there is no dot corresponding to μ=5.

The probability that sample mean will be equal to population mean forn=3is0.

06

Part (e) Step 1. Find the probability that sampling error made in estimating the population mean.

Number of dots within 0.5or less of μ=5is 1out of 3 when n is 1and 2.

For n=3, there is no dots are included in the sample mean x¯will be 0.5or less of μ.

Hence, the probability that x¯will be within 0.5or less of μis for n=1is 13.

Similarly, the probability that x¯will be within 0.5or less of μfor n=2is 13.

And the probability that x¯ will be withindata-custom-editor="chemistry" 0.5or less ofμforn=3is0.

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Most popular questions from this chapter

Suppose that a simple random sample is taken without replacement from a finite population of size N.

Part (a): Show mathematically that Equations (7.1) and (7.2) are identical for samples of size 1.

Part (b): Explain in words why part (a) is true.

Part (c): Without doing any computations, determine r for samples of size N without replacement. Explain your reasoning.

Part (d): Use Equation(7.1) to verify your answer in part (c).

Does the sample size have an effect on the mean of all possible sample means? Explain your answer.

Explain why increasing the sample size tends to result in a smaller sampling error when a sample means is used to estimate a population mean.

A variable of a population is normally distribution with mean μand standard deviation σ.

a. Identify the distribution of x.

b. Does your answer to part (a) depend on the sample size? Explain your answer.

c. Identify the mean and the standard deviation of x.

d. Does your answer to part (c) depend on the assumption that the variable under consideration is normally distributed? Why or why not?

Testing for Content Accuracy. A brand of water-softener salt comes in packages marked "net weight 40lb." The company that packages the salt claims that the bags contain an average of 40lbof salt and that the standard deviation of the weights is 1.5lbAssume that the weights are normally distributed.

a. Obtain the probability that the weight of one randomly selected bag of water-softener salt will be 39lb or less, if the company's claim is true.

b. Determine the probability that the mean weight of 10 randomly selected bags of water-softener salt will be 39lb or less, if the company's claim is true.

c. If you bought one bag of water-softener salt and it weighed 39lb, would you consider this evidence that the company's claim is incorrect? Explain your answer.

d. If you bought 10 bags of water-softener salt and their mean weight was 39lb, would you consider this evidence that the company's claim is incorrect? Explain your answer.

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