Population data: 1,2,3,4.

Part (a): Find the mean, μ, of the variable.

Part (b): For each of the possible sample sizes, construct a table similar to Table 7.2on the page 238and draw a dotplot for the sampling for the sampling distribution of the sample mean similar to Fig 7.1on page 293.

Part (c): Construct a graph similar to Fig 7.3and interpret your results.

Part (d): For each of the possible sample sizes, find the probability that the sample mean will equal the population mean.

Part (e): For each of the possible sample sizes, find the probability that the sampling error made in estimating the population mean by the sample mean will be 0.5or less, that is, that the absolute value of the difference between the sample mean and the population mean is at most 0.5.

Short Answer

Expert verified

Part (a): The mean μis .

Part (b): When localid="1652554566396" n=1,

When localid="1652554568737" n=2,

When localid="1652554572723" n=3,

When localid="1652554575601" n=4,

Part (c): The dot plot is given below,

Part (d): The probability that the sample mean will equal the population mean are 0,13,0,1.

Part (e): The probability that the sampling error made in estimating the population are12,23,1,1.

Step by step solution

01

Part (a) Step 1. Given information 

Consider the given question,

The population data is1,2,3,4.

02

Part (a) Step 2. Find the mean of the variable.

The mean μis given below,

μ=xiN=1+2+3+44=104=2.5

03

Part (b) Step 1. Construct the table.

For each of the possible sample sizes, we construct a table.

If the sample size taken n=1,


If the sample size taken n=2,

If the sample size taken n=3,

If the sample size taken n=4,

04

Part (c) Step 1. Construct the dot plot.

We will construct the dot plot for the sampling distribution of the sample mean.

To construct dot plot for the sampling distribution of the sample mean,

05

Part (d) Step 1. Find the probability that the sample mean will equal the population mean.

We can observe that from the dot plot there is no dot corresponding to μ=2.5 when n is 1.

Hence, the probability that sample mean will be equal to population mean=04=0

Similarly, the probability that sample mean will be equal to population mean for =26=13(As there are 2dots corresponding μ=2.5)

The probability that sample mean will equal to population mean for n=3is 1(As there are one dots corresponding μ=2.5)

06

Part (e) Step 1. Find the probability that sampling error made in estimating the population mean.

We need to find the probability that the sampling error made in estimating the population mean by the sample mean will be 0.5or less, that is the probability that xwill be within 0.5or less of μ.

Number of dots within 0.5or less of μ=2.5is 2out of 4for n=1.

Hence, the probability that xwill be within 0.5or less of μis 24=12.

Number of dots within 0.5or less of μ=2.5is 4out of role="math" localid="1652554136075" 6for n=2.

Hence, the probability that xwill be within 0.5or less of μis 44=1.

Number of dots within 0.5or less data-custom-editor="chemistry" μ=2.5is 4out of data-custom-editor="chemistry" 4for n=3.

Hence, the probability that x¯ will be within0.5or less ofμis1.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Refer to Exercise 7.7 on page 295.

a. Use your answers from Exercise 7.7(b) to determine the mean, μs, of the variable x¯for each of the possible sample sizes.

b. For each of the possible sample sizes, determine the mean, μs, of the variable x¯, using only your answer from Exercise 7.7(a).

7.54 Unbiased and Biased Estimators. A statistic is said to be an unbiased estimator of a parameter if the mean of all its possible values equals the parameter. otherwise, it is said to be a biased estimator. An unbiased estimator yields, on average, the correct value of the parameter, whereas a biased estimator does not.
a. Is the sample mean an unbiased estimator of the population mean? Explain your answer.
b. Is the sample median an unbiased estimator of the population median? (Hint: Refer to Example 7.2 on pages 292-293. Consider samples of size 2.)

Suppose that a simple random sample is taken without replacement from a finite population of size N.

Part (a): Show mathematically that Equations (7.1) and (7.2) are identical for samples of size 1.

Part (b): Explain in words why part (a) is true.

Part (c): Without doing any computations, determine r for samples of size N without replacement. Explain your reasoning.

Part (d): Use Equation(7.1) to verify your answer in part (c).

7.47 Baby Weight. The paper "Are Babies Normal?" by T. Clemons and M. Pagano (The American Statistician, Vol. 53, No, 4. pp. 298-302) focused on birth weights of babies. According to the article, the mean birth weight is3369 grams (7 pounds, 6.5 ounces) with a standard deviation of 581 grams.
a. Identify the population and variable.
b. For samples of size 200, find the mean and standard deviation of all possible sample mean weights.
c. Repeat part (b) for samples of size400.

A variable of a population is normally distribution with mean μand standard deviation σ.

a. Identify the distribution of x.

b. Does your answer to part (a) depend on the sample size? Explain your answer.

c. Identify the mean and the standard deviation of x.

d. Does your answer to part (c) depend on the assumption that the variable under consideration is normally distributed? Why or why not?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free