In Problems 3–6, find the critical point set for the given system.

dxdt=x-y,dydt=x2+y2-1

Short Answer

Expert verified

The critical points are12,12,-12,-12

Step by step solution

01

Find critical points

Consider the system as:

dxdt=x-ydydt=x2+y2-1

For finding the critical points put the system equal to 0.

So,

x-y=0x=yx2+y2-1=0x2+y2=1

02

Solve for x and y

Put the value of y in another equation and solve, then;

x2+x2=12x2=1x=±12

Thus, the critical points are(12,12),(-12,-12).

This is the required result.

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