Predator-Prey Model.The Volterra–Lotka predator-prey model predicts some rather interesting behavior that is evident in certain biological systems. For example, suppose you fix the initial population of prey but increase the initial population of predators. Then the population cycle for the prey becomes more severe in the sense that there is a long period of time with a reduced population of prey followed by a short period when the population of prey is very large. To demonstrate this behavior, use the vectorized Runge–

Kutta algorithm for systems withh=0.5to approximate the populations of prey xand of predators yover the period [0, 5] that satisfy the Volterra–Lotka systemx'=x(3-y),y'=y(x-3)

under each of the following initial conditions:

(a)x(0)=2,y(0)=4(b)x(0)=2,y(0)=5(c)x(0)=2,y(0)=7

Short Answer

Expert verified

The solution can get by the Matlab method.

Step by step solution

01

Transform the equation

Write the equation asx'=x3-yandy'=yx-3

The initial conditions are:

role="math" localid="1664099345245" x1(0)=2,2,2x2(0)=4,5,7

02

Apply Runge –Kutta method

For the solution apply the Runge-Kutta method in MATLAB for

Now the algorithm is:

function[t,x] =Runge_Kutta(f,t0,t_end,init_cond,h)
%we begin at time t0 and end when we reach t_end
%init_cond(i) contains the initial value of x_i
%f contains functions such that x_i'=f_i(t,x1,x2,...)

t(:,1)=t0; % t0 is the initial value of t
x(:,1)=init_cond; % initial conditions are set

i=1;
while t(:,i) < t_end

k1=f(t(i),x(:,i));
k2=f(t(i)+0.5*h,x(:,i)+0.5*h*k1);
k3=f(t(i)+0.5*h,x(:,i)+0.5*h*k2);
k4=f(t(i)+h,x(:,i)+h*k3);

x(:,i+1)=x(:,i)+(h/6)*(k1+2*k2+2*k3+k4);

t(:,i+1)=t(:,i)+ h;
i=i+1;

end

Now

clear all

init_cond_a=[2;4];
init_cond_b=[2;5];
init_cond_c=[2;7];

f=@(t,X) [X(1)*(3-X(2));X(2)*(X(1)-3)];

[t,xa] = Runge_Kutta(f,0,5,init_cond_a,0.5);
[t,xb] = Runge_Kutta(f,0,5,init_cond_b,0.5);
[t,xc] = Runge_Kutta(f,0,5,init_cond_c,0.5);


table(t',xa(1,:)',xa(2,:)',xb(1,:)',xb(2,:)',xc(1,:)',xc(2,:)','VariableNames',{'t','x_part_a','y_part_a','x_part_b','y_part_b','x_part_c','y_part_c'})

t

X for a

Y for a

X for b

Y for b

X for c

Y for b

0

2

4

2

5

2

7

0.5

1.95

2.25

1.48

2.42

0.91

2.79

1

3.34

1.836

2.66

1.45

1.63

1.13

1.5

4.53

3.365

5.19

2.40

4.49

1.07

2

2.47

4.32

3.10

4.649

5.96

5.47

2.5

1.96

2.719

1.92

3.32

1.518

5.93

3

2.86

1.96

2.34

2.05

0.95

2.18

This is the required result.

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