In Problem 19, solve the given initial value problem

y'''y''4y'+4y=0y(0)=4y'(0)=1y''(0)=19

Short Answer

Expert verified

The solution is Cy(t)=et3e2t2e2t

Step by step solution

01

Basic differentiation

The Sum rule says the derivative of a sum of functions is the sum of their derivatives. The Difference rule says the derivative of a difference of functions is the difference of their derivatives.

02

Solving by basic differentiation:

We will do the following question on the basis of basic differentiation ;

r3r24r+4=0r34r2+7r6=(r1)(r2)(r+2)=0y(t)=c1et+c2e2t+c3e2ty'(t)=c1et+2c2e2t2c3e2ty''(t)=c1et+4c2e2t+4c3e2ty(0)=4y'(0)=1y''(0)=19y(t)=et3e2t2e2t

Hence, the final answer is:

y(t)=et3e2t2e2t

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