Implicit Function Theorem. Let G(x,y)have continuous first partial derivatives in the rectangleR={x,y:a<x<b,c<y<d}containing the pointlocalid="1664009358887" (x0,y0). IfG(x0,y0)=0 and the partial derivativeGy(x0,y0)0, then there exists a differentiable function y=ϕ(x), defined in some intervalI=(x0-δ,y0+δ),that satisfies G for allforG(x,ϕx)all xI.

The implicit function theorem gives conditions under which the relationshipG(x,y)=0 implicitly defines yas a function of x. Use the implicit function theorem to show that the relationshipx+y+exy=0 given in Example 4, defines y implicitly as a function of x near the point(0,-1).

Short Answer

Expert verified

The given relationship implicitly defines y as a function of x near thepoint0,-1.

Step by step solution

01

Finding the partial derivative of the given relation concerning y

yx+y+exy=1+xexy

02

Determining whether the given relation defines y implicitly as a function of x or not

As one sees in Step 1, the partial derivative of the given relation is not equal to zero for all x in the interval0.-1.

Hence, the given relationship x+y+exy=0defines y implicitly as a function of x near the point (0,-1).

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