In Problems 1 and 2, verify that the pair x(t), and y(t) is a solution to the given system. Sketch the trajectory of the given solution in the phase plane.

dxdt=1,dydt=3x2;x(t)=t+1,y(t)=t3+3t2+3t

Short Answer

Expert verified

Hence, it is verified that xt,yt is a solution to the given system.

Step by step solution

01

Get the result in form of x and y

Here the system is;

dxdt=1dydt=3x2

And

x(t)=t+1y(t)=t3+3t2+3t

Then

dxdt=1dydt=3(t2+2t+1)=3(t+1)2=3(x(t))2

Therefore, the pair (x(t), y(t)) is a solution to the system.

Also,

y(t)+1=t3+3t2+3t+1=(t+1)3=(x(t))3y=x3-1

02

Get the result

Sincedxdt=1x is increasing,the flow is from left to right along the curve.

03

Sketch

This is the required result.

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