Use Euler’s method with step size h = 0.1 to approximate the solution to the initial value problem

y'=x-y2, y (1) = 0 at the points x=1.1,1.2,1.3,1.4and1.5.

Short Answer

Expert verified
xn
1.11.21.31.41.5
yn
0.1
0.209
0.325
0.444
0.564

Step by step solution

01

Write the recursive formula

For the solution use the Euler’s formulayn+1=yn+h.fxn,yn

02

Apply recursive formula

We have, fx,y=x-y2,x0=1,y0=0,h=0.1

Then,yn+1=yn+h.fxn,yn=yn+0.1x-y2

03

Put  n=0 to find  y1

Now, find the value of y1

y1=y0+0.1x0-y02=0+0.11=0.1

Hence, the value of y1=0.1 when x1=1.1

04

Put  n=1 to find  y2

The value of y2is

y2=y1+0.1x1-y12=0.1+0.11.1-0.01=0.1+0.109=0.209

Consequently, the value is y2=0.209 when x2=1.2

05

Put  n=2 to find  y3

Now the value of y3

y3=y2+0.1x2-y22=0.209+0.11.2-0.043=0.209+0.116=0.325

So, the value of y3=0.325 when x3=1.3

06

Put  n=3 to find  y4

The value of y4is

y4=y3+0.1x3-y32=0.325+0.11.3-0.106=0.325+0.119=0.444

Thus, the value is y4=0.444 when x4=1.4

07

Put  n=4 to find  y5

The value of y5is

y5=y4+0.1x4-y42=0.444+0.11.4-0.197=0.444+0.12=0.564

Therefore, the value is y5=0.564when x5=1.5

Therefore the solution is


role="math" localid="1663939345323" xn
1.11.21.31.41.5
yn
0.10.2090.325
0.444
0.564

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