Find a general solution to the given differential equation.4y''-4y'+10y=0

Short Answer

Expert verified

The general solution to the given differential equation is;

y=c1e12tcos3t2+c2e12tsin3t2

Step by step solution

01

The general solution if the roots are complex conjugate

If the roots of the auxiliary equation areα±iβ, then the general solution is given asyt=eαtc1cosβt+c2sinβt.

02

Write the auxiliary equation of the given differential equation

The given differential equation is4y''-4y'+10y=0.

The auxiliary equation for the above equation4m2-4m+10=0.

03

Find the roots of the auxiliary equation 

Solve the auxiliary equation,

4m2-4m+10=0m=--4±16-16024m=4±-1448m=4±12i8m=1±3i2

The roots of the auxiliary equation arem1=1+3i2&m2=1-3i2.

Thus, the general solution of the given equation isy=c1e12tcos3t2+c2e12tsin3t2.

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