Chapter 4: Q41E (page 165)
Find three linearly independent solutions (see Problem35) of the given third-order differential equation and write a general solution as an arbitrary linear combination of it.
y"' + 3y" - 4y' - 12y = 0.
Short Answer
The three independent solutions of the given differential equation are:
y1(t) = e2t,y2(t) = e-2t and y3(t) = e-3t
The general solution is y(t) = c1e2t + c2e-2t + c3e-3t