Find a general solution.y'''-y''+2y=0

Short Answer

Expert verified

The general solution of the given equation y'''-y''+2y=0isy(t)=C1e-t+C2etcos(t)+C3etsin(t).

Step by step solution

01

Using rational root theorem.

First, you need to find the auxiliary equation and solve it. One has r3-r2+2=0.

The first divisor of role="math" localid="1654074445353" 2is 1 if 1will be one solution of the equation and (r-1) will be a factor.

That doesn't happen, but next, you can try with -1 so thatr+1 would be a factor.

02

Finding factor

Now you can divide r3-r2+2by r+1to get r2-2r+2.

Therefore, the equation can be factored as (r+1)(r2-2r+2)=0

Since r2-2r+2=0

role="math" localid="1654074733241" r=2±22-4×1×22r=1±i

03

Finding roots.

The roots of the auxiliary equation are r=-1,r=1+iand r=1-i

Thus, the general solution of the differential equation is:

y(t)=C1e-t+C2etcos(t)+C3etsin(t)

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