A nonhomogeneous equation and a particular solution are given. Find a general solution for the equation. y''=2y+2tan3x,      yp(x)=tanx

Short Answer

Expert verified

The general solution of the given differential equation isy=c1e2x+c2e-2x+tanx.

Step by step solution

01

Firstly, write the auxiliary equation of the given differential equation

The differential equation is,

y''=2y+2tan3xy''-2y=2tan3x                     (1)

Write the homogeneous differential equation of the equation (1),

y''-2y=0

The auxiliary equation for the above equation,

m2-2=0

02

Now find the complementary solution of the given equation is

Solve the auxiliary equation,

m2-2=0m=±2

The roots of the auxiliary equation are,

m1=2,   &   m2=-2

The complementary solution of the given equation is,

yc=c1e2x+c2e-2x

03

Use the given particular solution to find a general solution for the equation.

The given particular solution,

yp(x)=tanx

Therefore, the general solution is,

y=yc(x)+yp(x)y=c1e2x+c2e-2x+tanx

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