Question: Find a synchronous solution of the form AcosΩt+BsinΩtto the given forced oscillator equation using the method of Example 4 to solve for A and By''+2y'+4y=6cos2t+8sin2t,Ω=2.

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Short Answer

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Answer

The synchronous solution to the given forced oscillator equation isyt=-2cos2t+32sin2t.

Step by step solution

01

Finding the differential equation of  Y

Given differential equation isy''+2y'+4y=6cos2t+8sin2t,Ω=2.

The synchronous solution of the formy=Acos2t+Bsin2t.

Now substitute the value of y in the differential equation;

y'(t)=-2Asin2t+2Bcos2t1y''(t)=-4Acos2t-4Bsin2t2

02

Substitute the y'  & y''  in the given equation.

Substitute and in the differential equation;

-4Acos2t-4Bsin2t+2(-2Asin2t+2Bcos2t)+4(Acos2t+Bsin2t)=6cos2t+8sin2t4Bcos2t-4Asin2t=6cos2t+8sin2t

03

 Step 3: Finding the value of  B

Equate the coefficients ofcos2t, then4B=6 we get

B=64=32

04

Step 4: Finding the value of  A

Equate the coefficients of sin2t , then we get;

-4A=8A=-84A=-2

Therefore, the solution isy(t)=-2cos2t+32sin2t.

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