find a differential operator that annihilates the given function

x2ex-xsin4x+x3

Short Answer

Expert verified

D4(D-1)3D2+162is the differential operator that annihilates the given function.

Step by step solution

01

Any nonhomogeneous term of the form f(x)=xkeαxcosβx OR role="math" localid="1663946799201" xkeαxsinβxsatisfiesrole="math" localid="1663946761280" (D-α)2+β2m[f]=0for K=0,1,2,...,m-1

Let the function bef(x)=x2ex-xsin4x+x3

Letg(x)=x2ex

Then

(D-1)3[g]=0

Leth(x)=xe-5xsin3x

Then

D2+422[h]=0

Leti(x)=x3

Then

D4[i]=0

Hence

(D-1)3D2+162D4[f]=0D4(D-1)3D2+162[f]=0

ThenD4(D-1)3D2+162 is the differential operator that annihilates the given function.

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