Find a general solution for the differential equation with x as the independent variable:y'''3y''y'+3y=0

Short Answer

Expert verified

The general solution for the differential equation with x as the independent variableis.y(x)=c1ex+c2e5x+c3e4x

Step by step solution

01

Auxiliary equation:

The auxiliary equation isr3+2r219r20=0

02

Inspecting the sum further:

By inspection, we find that r = -1 is a root and using polynomial division we get

r3+2r219r20=(r+1)(r2+r20)=(r+1)(r+5)(r4)=0

03

General solution:

Now the roots of auxiliary equation arer1=1,r2=5 and . r3=4Therefore, a general solution to given equation is

y(x)=c1ex+c2e5x+c3e4x

Hence the final solution isy(x)=c1ex+c2e5x+c3e4x

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Most popular questions from this chapter

Use the reduction of order method described in Problem 31 to find three linearly independent solutions to, given y'''-2y''+y'-2y=0that f(x)=e2xis a solution.

As an alternative proof that the functions er1x,er2x,er3x,...,ernxare linearly independent on (∞,-∞) when r1,r2,...rn are distinct, assume C1er1x+C2er2x+C3er3x+...+Cnernxholds for all x in (∞,-∞) and proceed as follows:

(a) Because the ri’s are distinct we can (if necessary)relabel them so that r1>r2>r3>...>rn.Divide equation (33) by to obtain C1+C2er2xer2x+C3er3xer3x+...+Cnernxernx=0Now let x→∞ on the left-hand side to obtainC1 = 0.(b) Since C1 = 0, equation (33) becomes

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and let x→∞ to conclude that C2 = 0.

(c) Continuing in the manner of (b), argue that all thecoefficients, C1, C2, . . . ,Cn are zero and hence er1x,er2x,er3x,...,ernxare linearly independent on(∞,-∞).

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Let y1x2= Cerx, where C (≠0) and r are real numbers,be a solution to a differential equation. Supposewe cannot determine r exactly but can only approximateit by r. Let (x) =Cerxand consider the error

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(a) If r andr~are positive, r ≠­ , show that the errorgrows exponentially large as x approaches + ∞.

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Determine whether the given functions are linearly dependent or linearly independent on the interval(0,) .

(a){e2x,x2e2x,e-x}

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