In Problems 1-6, use the method of variation of parameters to determine a particular solution to the given equation.

y'''+y'=tanx

Short Answer

Expert verified

The particular solution isyp=ln|secx|-sinxln|secx+tanx|

Step by step solution

01

Definition

Variation of parameters, also known as variation of constants, is a general method to solve inhomogeneous linear ordinary differential equations.

02

Find complementary solution

The given equation is:y'''+y'=tanx

The auxiliary equation isD3+D=0

So,D=±i,0

So {1,cosx,sinx}fundamental set.

03

Calculate Wornkians

The value of wronkians is:

W1cosxsinx=1cosxsinx0-sinxcosx0-cosx-sinx=1

W1=(-1)3-1Wcosxsinx=cosxsinx-sinxcosx=1W2=(-1)3-2W1sinx=-cosxW3=(-1)3-3W1cosx=-sinx

04

For particular solution

The particular solution is given by:

yp=11(tanx)1dx+cosx-cosx(tanx)1dx+sinx-sinx·tanx1dxyp=ln|secx|+cos2x+sinxI1I1=-sinx·tanxdx=sinx-ln(secx+tanx)

yp=ln|secx|+cos2x+sin2x-sin2xln(secx+tanx)

Since 1 is in fundamental set solution soyp=ln|secx|-sinxln|secx+tanx|

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Most popular questions from this chapter

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