Find the area of each figure:

It can be seenthat the lower part of the figure is a rectangle with length 8 and 4 width

The upper part of the figure is an isosceles triangle with sides$5,5,8$

Since the lower part is a rectangle andarea ofrectanglecan be found using the formula$A=lb$

Where,

i= Length of arectangleandb= Width of arectangle

So, the area of lower part$A_1=8\times 4$

=32

As theupper part of the figure is an isosceles triangle and the area of an triangle can be found using

$A=\frac{1}{2}bh$

b= Base of a triangle and h= Height of a triangle

We use Pythagorean Theorem.

Pythagorean Theorem define that in a right angle triangle, the square of the hypotenuse is equal to the sum of squares of other sides.

$5^2=P^2+4^2$

$P^2=25-16$

$P^2=9$

$P=3$

Thus, the area of triangle

$A_2=\frac{1}{2}\left(3\right)\left(8\right)$

$=12$

Total area of the figure$A=A_1+A_2$

$=32+12$

=44 Square units

Therefore, the area of given figure is44 square units.