Consecutive sides of the figures are perpendicular. Find the area of each figure.

Consecutive sides of the figure is perpendicular.

If b is the base of the reactangle and h is the height of the rectangle.

Then, the area of the rectangle is$A=b\times h$

Measurement of first part of the figure is –height $\left(h\right)=(7+5+2=14),$

$base\left(b\right)=5$

Put the value of base and height into the formula and find the area of the figure:

$\begin{array}{c}{A}_1=5\times 14\\ =70\end{array}$

Measurement of the second part of the figure is-height$\left(h\right)=6,$$base\left(b\right)=5$

Put the value of base and height into the formula and find the area of the figure:$\begin{array}{c}{A}_2=5\times 6\\ =30\end{array}$

Measurement of the third part of the figure is –height$\left(h\right)=6,$$base\left(b\right)=5$

Put the value of base and height into the formula and find the area of the figure:$\begin{array}{c}{A}_3=5\times 6\\ =30\end{array}$

Now,the total area of the figure –

$\begin{array}{c}A=A_1+A_2+A_3\\ =70+30+30\\ =130\end{array}$

Therefore, the area of the figure$\left(A\right)=130$