Consecutive sides of the figures are perpendicular. Find the area of each figure.

Consecutive sides of the figure is perpendicular.

If b is the base of the reactangle and h is the height of the rectangle.

Then, the area of the rectangle is$A=b\times h$

Measurement of first part of the figure is –height $\left(h\right)=2,$$base\left(b\right)=2.8$

Put the value of base and height into the formula and find the area of the figure:$\begin{array}{c}{A}_1=2.8\times 2\\ =5.6\end{array}$

Measurement of the second part of the figure is-height$\left(h\right)=4,$$base\left(b\right)=2.8$

Put the value of base and height into the formula and find the area of the figure:$\begin{array}{c}{A}_2=2.8\times 4\\ =11.2\end{array}$

Measurement of the third part of the figure is –height$\left(h\right)=6,$$base\left(b\right)=2.8$

Put the value of base and height into the formula and find the area of the figure:$\begin{array}{c}{A}_3=2.8\times 6\\ =16.8\end{array}$

Measurement of the fourth part of the figure is –height$\left(h\right)=8,$$base\left(b\right)=2.8$

Put the value of base and height into the formula and find the area of the figure:$\begin{array}{c}{A}_4=2.8\times 8\\ =22.4\end{array}$

Now,the total area of the figure –

$\begin{array}{c}A=A_1+A_2+A_3+A_4\\ =5.6+11.2+16.8+22.4\\ =56\end{array}$

Therefore, the area of the figure$\left(A\right)=56$