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Geometry

Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

$Math Studyset Vaia Explanations$ Math

Student Edition · 227 pages

ISBN: 9780395977279

Chapter 11: Q21. (page 426)

Consecutive sides of the figures are perpendicular. Find the area of each figure.

Short Answer

Expert verified

Area of the figure $(A) = 49.4 s q . u n i t s$

Step by step solution

01

Step 1. Given information.

Consecutive sides of the figure is perpendicular.

02

Step 2. Concept Used.

Since the two triangles are right angles triangle.

Where, i is the base of the triangles ,b is the height of the triangles and H is the Hypotenuse of the triangles.

$\begin{array}{l} Sin 26^{0} = \frac{b}{10} \\ b = 10 Sin 26^{0} \\ Cos 26^{0} = \frac{l}{10} \\ l = 10 Cos 26^{0} \end{array}$

03

Step 3. Let’s calculate the area of the figure.

Now, area of the figure

$\begin{matrix} A = (b \times l) \\ = (10 \sin 26^{0}) \times (10 \cos 26^{0}) \\ = (49.4) s q . u n i t s \end{matrix}$

Therefore, the area of the figure $(A) = 49.4 s q . u n i t s$

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