Find the area of given figure?

Consecutive sides of the figure is perpendicular.

If b is the base of the reactangle and i is the height of the rectangle.

Then, the area of the rectangle is
$A=b\times l$

Value of first part of the figure is –height $\left(l\right)=y,$$base\left(b\right)=2y$

Put the value of base and height into the formula and find the area of the figure:

$\begin{array}{c}{A}_1=\left(2y\right)\times \left(y\right)\\ =2y^2\end{array}$

Value of the second part of the figure is-height $\left(l\right)=2y,$$base\left(b\right)=4y$

Put the value of base and height into the formula and find the area of the figure:

$\begin{array}{c}{A}_2=\left(4y\right)\times \left(2y\right)\\ =8y^2\end{array}$

Value of the third part of the figure is –height $\left(l\right)=3y,$$base\left(b\right)=8y$

Put the value of base and height into the formula and find the area of the figure:$\begin{array}{c}{A}_3=\left(8y\right)\times \left(3y\right)\\ =24y^2\end{array}$

Now,

The total area of the figure –$\begin{array}{l}A=A_1+A_2+A_3\\ A=2y^2+8y^2+24y^2\\ A=34y^2\end{array}$

Therefore, the area of the figure $\left(A\right)=34y^2$