Chapter 9: Q4. (page 335)

$\bar{J T}$ is tangent to $⊙$ $O$ at $T$ . Complete.
If $J K = 9$ and $K O = 8$ , then $J T = ?$

Short Answer

Expert verified

The value of $J T = 3 \sqrt{17}$ .

Step by step solution

Step 1. Given information.

It is given that, $J K = 9, K O = 8$ in the figure,

$\begin{array}{l} J O = J K + K O \\ = 17 \end{array}$

Let, $J T = x$

Step 2. Concept used.

When a secant segment and a tangent segments are drawn to a circle from an external point then the product of the secant segment and its external segment is equal to the square of the tangent segment.

Therefore, from the given figure,

$\begin{matrix} J T^{2} = J K \times J O \\ x^{2} = 9 \times 17 \\ x^{2} = 153 \\ x = 3 \sqrt{17} \end{matrix}$

Step 3. Neglect negative sign.

Since, length is positive

So, neglecting the negative value.

Therefore, the value of $J T = 3 \sqrt{17}$ .

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$\bar{J T}$ is tangent to $⊙$ $O$ at $T$ . Complete.
If $J K = 9$ and $K O = 8$ , then $J T = ?$

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Concept used.

Step 3. Neglect negative sign.

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JT¯is tangent to ⊙Oat T. Complete.If JK=9 and KO=8, then JT=?

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Concept used.

Step 3. Neglect negative sign.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Logic and Functions

Pure Maths

Mechanics Maths

Applied Mathematics

Discrete Mathematics

Statistics

Study anywhere. Anytime. Across all devices.

$\bar{J T}$ is tangent to $⊙$ $O$ at $T$ . Complete.
If $J K = 9$ and $K O = 8$ , then $J T = ?$