Chapter 4: Q2 (page 121)

Given: $\bar{FC}$ and $\bar{SH}$ bisect each other at $A;$ localid="1638250328146" $FC = SH$ .
Prove: $SA = AC$ .

Short Answer

Expert verified

It is proved that $\bar{A C} = \bar{S A}$ .

Step by step solution

Step 1. Consider the diagram.

Here, $\bar{F C}$ , $\bar{S H}$ bisect each other $A$ and $\bar{F C} = \bar{S H}$

Step 2. State the proof.

As $\bar{F C}$ , $\bar{S H}$ bisect each other $A$ ,

$\bar{A C} = \frac{1}{2} (\bar{F C})$ and $\bar{S A} = \frac{1}{2} (\bar{S H})$

Also,

$\bar{F C} = \bar{S H}$ (Given)

Multiply both sides by $\frac{1}{2}$ .

$\begin{matrix} \frac{1}{2} (\bar{F C}) = \frac{1}{2} (\bar{S H}) \\ \bar{A C} = \bar{S A} \end{matrix}$

Step 3. State the conclusion.

Therefore, $\bar{A C} = \bar{S A}$ (proved).

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Given: $\bar{FC}$ and $\bar{SH}$ bisect each other at $A;$ localid="1638250328146" $FC = SH$ .
Prove: $SA = AC$ .

Short Answer

Step by step solution

Step 1. Consider the diagram.

Step 2. State the proof.

Step 3. State the conclusion.

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Given: FC¯ and SH¯ bisect each other at A;localid="1638250328146" FC=SH.Prove: SA=AC.

Short Answer

Step by step solution

Step 1. Consider the diagram.

Step 2. State the proof.

Step 3. State the conclusion.

One App. One Place for Learning.

Most popular questions from this chapter

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Given: $\bar{FC}$ and $\bar{SH}$ bisect each other at $A;$ localid="1638250328146" $FC = SH$ .
Prove: $SA = AC$ .