Chapter 13: Q. 17 (page 526)

Find the center and radius of each circle.
${(x + 3)}^{2} + y^{2} = 49$

Short Answer

Expert verified

The center is (-3, 0) and the radius is 7.

Step by step solution

Step-1 – Given

The given equation is ${(x + 3)}^{2} + y^{2} = 49$ .

Step-2 – To determine

We have to find the center and the radius of the given circle.

Step-3 – Calculation

We compare the given equation ${(x + 3)}^{2} + y^{2} = 49$ with the standard form of a circle: ${(x - a)}^{2} + {(y - b)}^{2} = r^{2}$ .

Here (a, b) is the center and r being the radius.

Comparing the two equations we get: a = - 3, b = 0andr = 7.

So, the center is (-3, 0) and the radius is 7.

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Find the center and radius of each circle.
${(x + 3)}^{2} + y^{2} = 49$

Short Answer

Step by step solution

Step-1 – Given

Step-2 – To determine

Step-3 – Calculation

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Find the center and radius of each circle.
${(x + 3)}^{2} + y^{2} = 49$