Chapter 13: Q. 19 (page 526)

Find the center and radius of each circle.
${(x - j)}^{2} + {(y + 14)}^{2} = 17$

Short Answer

Expert verified

The center is (j, -14) and the radius is $\sqrt{17}$ .

Step by step solution

Step-1 – Given

The given equation is ${(x - j)}^{2} + {(y + 14)}^{2} = 17$ .

Step-2 – To determine

We have to find the center and the radius of the given circle.

Step-3 – Calculation

We compare the given equation ${(x - j)}^{2} + {(y + 14)}^{2} = 17$ with the standard form of a circle: ${(x - a)}^{2} + {(y - b)}^{2} = r^{2}$ .

Here (a, b) is the center and r being the radius.

Comparing the two equations we get: a = j, b = -14andr = $\sqrt{17}$ .

So, the center is (j, -14) and the radius is $\sqrt{17}$ .

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Find the center and radius of each circle.
${(x - j)}^{2} + {(y + 14)}^{2} = 17$

Short Answer

Step by step solution

Step-1 – Given

Step-2 – To determine

Step-3 – Calculation

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Find the center and radius of each circle.x−j2+y+142=17

Short Answer

Step by step solution

Step-1 – Given

Step-2 – To determine

Step-3 – Calculation

One App. One Place for Learning.

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Find the center and radius of each circle.
${(x - j)}^{2} + {(y + 14)}^{2} = 17$