Chapter 2: Q12 (page 40)

Copy everything shown and supply missing statements and reasons.
Given: $S T = R N$ ; $I T = R U$
Prove: $S I = U N$
Proof;

Short Answer

Expert verified

From the given figure, it can be observed that some of $S I$ and $I T$ gives $S T$ , that is $S T = S I + I T$ .

From the given figure, it can be observed that some of $R U$ and $U N$ gives $R N$ , that is $R U + U N = R N$ .

Step by step solution

Step 1. Apply segment addition postulate.

From the given figure, it can be observed that some of $S I$ and $I T$ gives $S T$ , that is $S T = S I + I T$ .

From the given figure, it can be observed that some of $R U$ and $U N$ gives $R N$ , that is $R U + U N = R N$ .

Step 2. Apply Substitution property.

Substitute $S I + I T$ for $S T$ and $R U + U N$ for $R N$ in $S T = R N$ .

$\begin{matrix} S T = R N \\ S I + I T = R U + U N \end{matrix}$

Step 3. Apply subtraction property of algebra to step 2.

If $a = b$ and $c = d$ , then $a - c = b - d$ .

$\begin{matrix} S I + I T = I T + U N \\ S I = U N \end{matrix}$

Hence it is proved that $S I = U N$ .

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Copy everything shown and supply missing statements and reasons.
Given: $S T = R N$ ; $I T = R U$
Prove: $S I = U N$
Proof;

Short Answer

Step by step solution

Step 1. Apply segment addition postulate.

Step 2. Apply Substitution property.

Step 3. Apply subtraction property of algebra to step 2.

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Copy everything shown and supply missing statements and reasons.Given:ST=RN;IT=RUProve: SI=UNProof;

Short Answer

Step by step solution

Step 1. Apply segment addition postulate.

Step 2. Apply Substitution property.

Step 3. Apply subtraction property of algebra to step 2.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Calculus

Statistics

Geometry

Probability and Statistics

Decision Maths

Discrete Mathematics

Study anywhere. Anytime. Across all devices.

Copy everything shown and supply missing statements and reasons.
Given: $S T = R N$ ; $I T = R U$
Prove: $S I = U N$
Proof;