Chapter 5: Q12 (page 187)

Quad. SLTM is a rhombus.
If $m ∠ 1 = 3 x + 8$ and $m ∠ 2 = 11 x - 24$ find the value of x.

Short Answer

Expert verified

The value of x is 4.

Step by step solution

Step 1. Description of step.

Diagonals of a rhombus bisect the vertex angles.

Here, $∠ L S M$ is divided into $∠ 1 and ∠ 2$ , that is, $m ∠ 1 = m ∠ 2$ .

Step 2. Description of step.

Substitute $3 x + 8$ for $m ∠ 1$ and $11 x - 24$ into $m ∠ 1 = m ∠ 2$ .

$\begin{matrix} 3 x + 8 = 11 x - 24 \\ 11 x - 3 x = 24 + 8 \\ 8 x = 32 \end{matrix}$

Step 3. Description of step.

Divide each side of the obtained equation in steps 2 by 8 to find the value of x.

$\begin{matrix} \frac{8 x}{8} = \frac{32}{8} \\ x = 4 \end{matrix}$

Therefore, the value of x is 4.

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Quad. SLTM is a rhombus.
If $m ∠ 1 = 3 x + 8$ and $m ∠ 2 = 11 x - 24$ find the value of x.

Short Answer

Step by step solution

Step 1. Description of step.

Step 2. Description of step.

Step 3. Description of step.

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Quad. SLTM is a rhombus.Ifm∠1=3x+8 andm∠2=11x-24 find the value of x.

Short Answer

Step by step solution

Step 1. Description of step.

Step 2. Description of step.

Step 3. Description of step.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Logic and Functions

Mechanics Maths

Pure Maths

Geometry

Discrete Mathematics

Applied Mathematics

Study anywhere. Anytime. Across all devices.

Quad. SLTM is a rhombus.
If $m ∠ 1 = 3 x + 8$ and $m ∠ 2 = 11 x - 24$ find the value of x.