Chapter 5: Q13 (page 193)

In Exercises 12-20, $TA = AB = BC$ and $TD = DE = EF$
Write an equation that relates $AD, BE$ and $CF$ . (Hint: Think of trapezoid CFDA).

Short Answer

Expert verified

The equation that relates AD, BEand CF is $2 BE = AD + CF$ .

Step by step solution

Step 1. Highlight a trapezoid in the given figure.

Step 2. Description of step.

Consider a trapezoid CFDA. From the figure, it can be observed that $B C = A B and E F = D E$ .

Step 3. Description of step.

From the figure, it can be observed that BE is the median of trapezoid CFDA. According to the property of the median of a trapezoid, the length of the median is the average of the two base lengths. Therefore,

$\begin{matrix} B E = \frac{1}{2} (A D + C F) \\ 2 B E = A D + C F \end{matrix}$

Therefore, the equation that relates AD, BEand CF is $2 B E = A D + C F$ .

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In Exercises 12-20, $TA = AB = BC$ and $TD = DE = EF$
Write an equation that relates $AD, BE$ and $CF$ . (Hint: Think of trapezoid CFDA).

Short Answer

Step by step solution

Step 1. Highlight a trapezoid in the given figure.

Step 2. Description of step.

Step 3. Description of step.

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In Exercises 12-20, TA=AB=BCand TD=DE=EFWrite an equation that relates AD,BEand CF. (Hint: Think of trapezoid CFDA).

Short Answer

Step by step solution

Step 1. Highlight a trapezoid in the given figure.

Step 2. Description of step.

Step 3. Description of step.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Mechanics Maths

Decision Maths

Discrete Mathematics

Theoretical and Mathematical Physics

Geometry

Calculus

Study anywhere. Anytime. Across all devices.

In Exercises 12-20, $TA = AB = BC$ and $TD = DE = EF$
Write an equation that relates $AD, BE$ and $CF$ . (Hint: Think of trapezoid CFDA).