Chapter 14: Q4. (page 574)

If $h (x) = 6 x + 1$ , find $h (\frac{1}{2})$ .Is $h$ a one-to-one function?

Short Answer

Expert verified

The value of $h (\frac{1}{2})$ is 4 and the function h isa one-to-one function.

Step by step solution

Step 1. Given Information.

Consider the given function $h (x) = 6 x + 1$ .

Step 2. Calculation.

Substitute $\frac{1}{2}$ for $x$ in the equation.

$\begin{array}{l} h (\frac{1}{2}) = 6 (\frac{1}{2}) + 1 \\ = 4 \end{array}$

So, the value of $h (\frac{1}{2})$ is 4.

To check whether a function is one-to-one or not, equation the image with pre image.

Let $h (x) = y$ .

$\begin{matrix} 6 x + 1 = y \\ \frac{y - 1}{6} = x \end{matrix}$

Step 3. Conclusion.

From the above equation, it is clear that each image has one pre image value. Therefore, the function h is one-to-one.

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If $h (x) = 6 x + 1$ , find $h (\frac{1}{2})$ .Is $h$ a one-to-one function?

Short Answer

Step by step solution

Step 1. Given Information.

Step 2. Calculation.

Step 3. Conclusion.

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If hx=6x+1, find h12.Is h a one-to-one function?

Short Answer

Step by step solution

Step 1. Given Information.

Step 2. Calculation.

Step 3. Conclusion.

One App. One Place for Learning.

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If $h (x) = 6 x + 1$ , find $h (\frac{1}{2})$ .Is $h$ a one-to-one function?