Chapter 11: Q. 11.22 (page 1069)

(a).Find the center and radius,then
(b).Graph the circle $x^{2} + y^{2} - 12 y + 11 = 0$

Short Answer

Expert verified

(a). Center $c = (0, 6)$ and radius $r = 5$

(b). Graph of the circle

Step by step solution

Part(a). Step 1.Given information

The equation of the given circle $x^{2} + y^{2} - 12 y + 11 = 0$

We have to find radius and center.

Also, we have to graph this circle.

Part (a) Step 2. Converting into standard circle form

find the values of x and y- terms,

$x^{2} + y^{2} - 12 y + 11 = 0 x^{2} + y^{2} - 12 y = - 11 x^{2} + y^{2} - 12 y + 36 = - 11 + 36 (x^{2} - 0) + (y^{2} - 12 y + 36) = 25 {(x - 0)}^{2} + {(y - 6)}^{2} = 5^{2}$

Which is the standard circle form with

circle= $(0, 6)$

radius = $5$

Part b.Step 1.Given information

The equation of the given circle $x^{2} + y^{2} - 12 y + 11 = 0$

Part b.Step 2.Graph of the circle.

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(a).Find the center and radius,then
(b).Graph the circle $x^{2} + y^{2} - 12 y + 11 = 0$

Short Answer

Step by step solution

Part(a). Step 1.Given information

Part (a) Step 2. Converting into standard circle form

Part b.Step 1.Given information

Part b.Step 2.Graph of the circle.

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(a).Find the center and radius,then(b).Graph the circlex2+y2-12y+11=0

Short Answer

Step by step solution

Part(a). Step 1.Given information

Part (a) Step 2. Converting into standard circle form

Part b.Step 1.Given information

Part b.Step 2.Graph of the circle.

One App. One Place for Learning.

Most popular questions from this chapter

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(a).Find the center and radius,then
(b).Graph the circle $x^{2} + y^{2} - 12 y + 11 = 0$