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Intermediate Algebra

OPENSTAX

$Math Studyset Vaia Explanations$ Math

OER 2017 Edition · 1346 pages

ISBN: 9780998625720

Chapter 11: Q. 406 (page 1069)

In the following exercises, factor completely
$24 a^{4} - 9 a^{3}$ .

Short Answer

Expert verified

The factors of the given expression are $3 a^{3} (8 a - 3)$ .

Step by step solution

01

Step 1. Given and explanation

We have $24 a^{4} - 9 a^{3}$ .

We can factorise this into simple expression by just taking common.

02

Step 2. Factorizing the expression.

We have $24 a^{4} - 9 a^{3}$

Therefore factorizing by taking common,

localid="1662126943015" $24 a^{4} - 9 a^{3} = 3 a^{3} (8 a - 3)$

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Most popular questions from this chapter

Multiply: $(a) (6 x + 5) (6 x - 5) (b) (4 p - 7 q) (4 p + 7 q)$

Perform the indicated operation and simplify.

$\frac{4 x}{x + 2} \cdot \frac{x^{2} + 5 x + 6}{12 x^{2}}$

Use the Quotient Property to simplify square roots.

(a) $\sqrt{\frac{72 x^{5}}{y^{6}}}$

(b) $\sqrt[5]{\frac{96 r^{11}}{s^{5}}}$

(c) $\sqrt[6]{\frac{128 u^{7}}{v^{12}}}$

In the following exercises,simplify

$(a) \frac{r^{\frac{5}{2}} . r^{- \frac{1}{2}}}{r^{- \frac{3}{2}}} (b) (\frac{36 s^{\frac{1}{5}} t^{- \frac{3}{2}}}{s^{- \frac{9}{5}} . t^{\frac{1}{2}}})$

For the function $f (x) = 25 x^{2} - 81$ , find:
(a) the zeros of the function.

(b) the x-intercepts of the graph

of the function.
(c) the y-intercept of the graph of the

function.

See all solutions

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