Chapter 11: Q.131 (page 1119)

In the following exercise, graph the equation $\frac{{(x + 3)}^{2}}{16} + \frac{{(y + 1)}^{2}}{4} = 1$

Short Answer

Expert verified

The required equation of a curve and graph is as follows $\frac{{(x + 3)}^{2}}{16} + \frac{{(y + 1)}^{2}}{4} = 1$

Step by step solution

Step 1, Given the information

The given equation of the curve $\frac{{(x + 3)}^{2}}{16} + \frac{{(y + 1)}^{2}}{4} = 1$

Step 2. Draw a graph

The standard equation of the ellipse is $\frac{{(x + 3)}^{2}}{16} + \frac{{(y + 1)}^{2}}{4} = 1$

Here, $16 > 4$ and $a^{2} = 16 a = \pm 4$

The major axis is horizontal and the center is $(- 3, - 1)$

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In the following exercise, graph the equation $\frac{{(x + 3)}^{2}}{16} + \frac{{(y + 1)}^{2}}{4} = 1$

Short Answer

Step by step solution

Step 1, Given the information

Step 2. Draw a graph

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In the following exercise, graph the equationx+3216+y+124=1

Short Answer

Step by step solution

Step 1, Given the information

Step 2. Draw a graph

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Applied Mathematics

Geometry

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Study anywhere. Anytime. Across all devices.

In the following exercise, graph the equation $\frac{{(x + 3)}^{2}}{16} + \frac{{(y + 1)}^{2}}{4} = 1$