Factor Trinomials of the Form ax2+bx+cusing the ‘ac’ Method.

6u2−46u−16

Short Answer

Expert verified

The solution is 2(u-8)(3u+1).

Step by step solution

01

Step 1. Given information

The given trinomial is 6u2−46u−16.

02

Step 2. Find greatest common factor.

Factor the greatest common factor.

6u2−46u−16=2(3u2-23u-8)

03

Step 3. Compare the trinomial 3u2-26u-8 to ax2+bx+c and then find the product of ac.

The values are as follows:

a=3b=-26c=-8

The product is as follows:

ac=3(-8)=-24

04

Step 4. Determine two numbers that multiply to ac and add to b.

Two numbers that multiply to acand add to bare as follows:

-24(1)=-24=ac-24+1=-23=b

So, two numbers are -24and 1.

Now, split the middle term of the trinomial 3u2-23u-8as follows:

3u2-23u-8=3u2-24u+u-8

05

Step  5. Factor by grouping.

3u2-23u-8=3u(u-8)+1(u-8)=(u-8)(3u+1)

06

Step 6. Check by multiplying all the factors 2(u-8)(3u+1).

2(u-8)(3u+1)=2(u2-24u+u-8)=2(u2-23u-8)=2u2-46u-16

Hence, the factor is 2(u-8)(3u+1).

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