Factor Trinomials of the Form ax2+bx+cusing the ‘ac’ Method.

48z3−102z2−45z

Short Answer

Expert verified

The solution is 3z(2z-5)(8z+3).

Step by step solution

01

Step 1. Given information

The given trinomial is 48z3−102z2−45z.

02

Step 2. Find greatest common factor.

Factor the greatest common factor.

48z3−102z2−45z=3z(16z2-34z-15)

03

Step 3. Compare the trinomial 16z2-34z-15 to ax2+bx+c and then find the product of ac. 

The values are as follows:

a=16b=-34c=-15

The product is as follows:

ac=16(-15)=-240

04

Step 4. Determine two numbers that multiply to ac and add to b. 

Two numbers that multiply to acand add to bare as follows:

-40(6)=-240=ac-40+6=-34=b

So, two numbers are -40and 6.

Now, split the middle term of the trinomial 16z2-34z-15as follows:

16z2-34z-15=16z2-40z+6z-15

05

Step  5. Factor by grouping.

16z2-34z-15=8z(2z-5)+3(2z-5)=(2z-5)(8z+3)

06

Step 6. Check by multiplying all the factors 3z(2z-5)(8z+3).

3z(2z-5)(8z+3)=3z(16z2-40z+6z-15)=3z(16z2-34z-15)=48z3-102z-45z

Hence, the factor is 3z(2z-5)(8z+3).

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