Chapter 6: Q 176 (page 603)

In the following exercises, factor completely using the difference of squares pattern, if possible.
$169 q^{2} - 1$

Short Answer

Expert verified

The complete factor of trinomial is $(13 q - 1) (13 q + 1)$ .

Step by step solution

Step 1. Given information

Consider the given trinomial.

$169 q^{2} - 1$

Step 2. Formula used

$a^{2} - b^{2} = (a + b) (a - b)$

Step 3. Write the trinomial as squares.

Write the trinomial as perfect squared form.

$169 q^{2} - 1 = {(13 q)}^{2} - 1^{2}$

Write them as product of conjugate.

${(13 q)}^{2} - 1^{2} = (13 q - 1) (13 q + 1)$

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In the following exercises, factor completely using the difference of squares pattern, if possible.
$169 q^{2} - 1$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Formula used

Step 3. Write the trinomial as squares.

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In the following exercises, factor completely using the difference of squares pattern, if possible.169q2-1

Short Answer

Step by step solution

Step 1. Given information

Step 2. Formula used

Step 3. Write the trinomial as squares.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Pure Maths

Theoretical and Mathematical Physics

Statistics

Discrete Mathematics

Calculus

Mechanics Maths

Study anywhere. Anytime. Across all devices.

In the following exercises, factor completely using the difference of squares pattern, if possible.
$169 q^{2} - 1$