Chapter 6: Q. 385 (page 635)

In the following exercise, factor completely using the perfect square trinomials pattern.
$40 x^{2} + 360 x + 810$

Short Answer

Expert verified

The factorisation of the given polynomial is

$40 x^{2} + 360 x + 810 = 10 {(2 x + 9)}^{2}$

Step by step solution

Step 1. Given information

The given polynomial is:

$40 x^{2} + 360 x + 810$

Step 2. Factorise the polynomial

We know that,

${(a + b)}^{2} = a^{2} + 2 a b + b^{2}$

For the polynomial $40 x^{2} + 360 x + 810$

Taking $10$ out as common, we get:

$10 (4 x^{2} + 36 x + 81)$

Now, simplifying, we get:

$10 [{(2 x)}^{2} + 2 \times 2 x + 9 + 9^{2}] 10 {(2 x + 9)}^{2}$

The factorisation of the given polynomial is $40 x^{2} + 360 x + 810 = 10 {(2 x + 9)}^{2}$

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In the following exercise, factor completely using the perfect square trinomials pattern.
$40 x^{2} + 360 x + 810$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Factorise the polynomial

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In the following exercise, factor completely using the perfect square trinomials pattern.40x2+360x+810

Short Answer

Step by step solution

Step 1. Given information

Step 2. Factorise the polynomial

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Probability and Statistics

Mechanics Maths

Theoretical and Mathematical Physics

Logic and Functions

Geometry

Calculus

Study anywhere. Anytime. Across all devices.

In the following exercise, factor completely using the perfect square trinomials pattern.
$40 x^{2} + 360 x + 810$