Chapter 6: Q. 407 (page 636)

In the following exercises, factor completely
$16 n^{2} - 56 m n + 49 m^{2}$ .

Short Answer

Expert verified

The factors of the given expression are ${(4 n - 7)}^{2}$ .

Step by step solution

Step 1. Given and explanation

We have $16 n^{2} - 56 m n + 49 m^{2}$ .

We know that

${(a - b)}^{2} = a^{2} - 2 a b + b^{2}$ .

Applying this, we will factorize the given expression.

Step 2. Factorizing the expression.

We have $16 n^{2} - 56 m n + 49 m^{2}$ .

Applying the property

role="math" localid="1644630473301" ${(a - b)}^{2} = a^{2} - 2 a b + b^{2} 16 n^{2} - 56 m n + 49 m^{2} = {(4 n)}^{2} - 2 (7) (4) m n + {(7 m)}^{2} = {(4 n - 7)}^{2}$

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In the following exercises, factor completely
$16 n^{2} - 56 m n + 49 m^{2}$ .

Short Answer

Step by step solution

Step 1. Given and explanation

Step 2. Factorizing the expression.

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In the following exercises, factor completely16n2-56mn+49m2.

Short Answer

Step by step solution

Step 1. Given and explanation

Step 2. Factorizing the expression.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Logic and Functions

Geometry

Applied Mathematics

Calculus

Pure Maths

Discrete Mathematics

Study anywhere. Anytime. Across all devices.

In the following exercises, factor completely
$16 n^{2} - 56 m n + 49 m^{2}$ .