Chapter 6: Q. 408 (page 636)

In the following exercises, factor completely
$6 a^{2} - 25 a - 9$ .

Short Answer

Expert verified

The factors of the given expression are $(3 a + 1) (2 a - 9)$ .

Step by step solution

Step 1. Given and explanation

We have $6 a^{2} - 25 a - 9$ .

We can see that this forms a quadratic equation which is given by

$x^{2} - a x + b = (x - c) (x - d)$

Step 2. Factorizing the expression.

We can see that this forms a quadratic equation which is given by

$x^{2} - a x + b = (x - c) (x - d)$

Therefore,

$6 a^{2} - 25 a - 9 = 6 a^{2} - 27 a + 2 a - 9 = 3 a (2 a - 9) + 1 (2 a - 9) = (2 a - 9) (3 a + 1)$

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In the following exercises, factor completely
$6 a^{2} - 25 a - 9$ .

Short Answer

Step by step solution

Step 1. Given and explanation

Step 2. Factorizing the expression.

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In the following exercises, factor completely6a2-25a-9.

Short Answer

Step by step solution

Step 1. Given and explanation

Step 2. Factorizing the expression.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Discrete Mathematics

Logic and Functions

Mechanics Maths

Pure Maths

Applied Mathematics

Decision Maths

Study anywhere. Anytime. Across all devices.

In the following exercises, factor completely
$6 a^{2} - 25 a - 9$ .