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Intermediate Algebra

OPENSTAX

$Math Studyset Vaia Explanations$ Math

OER 2017 Edition · 1346 pages

ISBN: 9780998625720

Chapter 6: Q. 6.92 (page 565)

Solve, $36 x^{2} = 121$

Short Answer

Expert verified

The value is $x = \pm \frac{11}{6}$

Step by step solution

01

Given information

Given the equation , $36 x^{2} = 121$

02

Write in standard form

Writing in standard form, we get

$36 x^{2} = 121 36 x^{2} - 121 = 0 (6 x - 11) (6 x + 11) = 0 x = \frac{11}{6}, - \frac{11}{6}$

03

Checking the values

Checking, we get

$36 {(\frac{11}{6})}^{2} = 121 36 \times \frac{121}{36} = 121 121 = 121$

This is true

04

Checking another value

Checking the value, we get

$36 {(- \frac{11}{6})}^{2} = 121 36 \times \frac{121}{36} = 121 121 = 121$

So this is true

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Most popular questions from this chapter

Factor by Grouping In the following exercises, factor by grouping.

$x^{2} - x + 4 x - 4$

Factor Trinomials of the Form $a x^{2} + b x + c$ Using Trial and Error.

role="math" localid="1644579317607" $5 x^{2} - 17 x + 6$

In the following exercises, factor completely using the sums and differences of cubes pattern, if possible.
$8 - 343 t^{3}$

Factor by Grouping In the following exercises, factor by grouping.

$a b + 5 a + 3 b + 15$

In the following exercises, factor completely.

$48 q^{3} - 24 q^{2} + 3 q$

See all solutions

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