In the following exercises, factor completely using trial and error.

p3-8p2-20p

Short Answer

Expert verified

The factorization of the expression is

p3-8p2-20p=p(p-10)(p+2)

Step by step solution

01

Step 1. Given Information

Consider the expression p3-8p2-20p.

The objective is to factor the expression completely by using the trial and error method.

02

Step 2. Factor the GCF

The GCF of the three terms in the expression is p. So factor the GCF from the expression we get

p3-8p2-20p=p×p2-p×8p-p×20=p(p2-8p-20)

03

Step 3. Factor using trial and error

The factors of the first term and the last term of the trinomial p2-8p-20are

p2=p·p-20=-10·2or-5·4

Consider all the combinations of factors


p2-8p-20
Possible FactorsProduct
role="math" localid="1644591886323" (p-10)(p+2)
role="math" localid="1644591843061" p2+2p-10p-20=p2-8p-20
(p+10)(p-2)
role="math" localid="1644591937645" p2-2p+10p-20=p2+8p-20
(p+5)(p-4)
role="math" localid="1644591952672" p2-4p+5p-20=p2+p-20
(p-5)(p+4)
role="math" localid="1644591961165" p2+4p-5p-20=p2-p-20

So the correct factors is (p-10)(p+2).

Thus,p3-8p2-20p=p(p-10)(p+2)

04

Step 4. Check the factors

Multiply the factors to check the solution

p(p-10)(p+2)=p(p2+2p-10p-20)=p(p2-8p-20)=p3-8p2-20p

And we get the given expression. So the expression is correctly factored.

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